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What is the slope of the line that passes through the points (-4, 6) and (2, 4)?
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\[slope=m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}\]
\[\large slope = \frac{y_2 - y_1 }{x_2 - x_1}\]
Use this substitution : \[(x_1=-4,y_1=6) \text{ and } (x_2=2,y_2=4)\]
thus, 4-6/2-(-4) = -2/6 = -1/3
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