Question

Find the 7th term of the sequence. -1,-2,-4,-8,.....

Answer 1

do you know what the sequence is?

Answer 2

\(T_n = r^{n - 1}\times a_1 \)

Answer 3

This is an Geometric progression where:

first term is -1 and common ratio is : -2/(-1) = 2

Answer 4

What is \(a_1\) and the ratio here?

Answer 5

So what is the 7th term of the sequence?

Answer 6

\[\large t_7 = (a) \cdot r^{7-1}\]

Put a and r here...

Answer 7

The equation to find the nth term would be
\[−(2^{n−1})\]
...just plug in 7 for n.

Answer 8

@lovejones2012 do you see what each number is multiplied by?

Answer 9

no

Answer 10

it's multiplied by 2
-1 x 2=-2 x 2=-4 x 2=-8 x 2=?

Answer 11

@lovejones2012 do you understand now?

Answer 12

no

Answer 13

everything is multiplied by 2