Question

4. What is the undefined value of 3b^2+13b+4/b+4? (1 point)

Answer 1

It has a removable singularity at b=-4.

\(3b^2+13b+4=(b+4)(3b+1)\) so \(\large \frac{3b^2+13b+4}{b+4}=3b+1\).

Now plug in b=-4 and your undefined value is -11.

I presume that's what you wanted.