Question

Identify the quadratic function with a parabola that opens downward.
y = -4x + x2
y = 6x2 – 3x
y = x2 – 13x -2
y = x – 3x2 + 10

Answer 1

y = x – 3x2 + 10 and

Answer 2

y = – 3x2 +x + 10

Answer 3

the negative sign infront of the squared value flips the parabola.

Answer 4

so it would be y = x – 3x2 + 10 ?

Answer 5

\[\left\{x^2-4 x,6 x^2-3 x,x^2-13 x-2,-3 x^2+x+10\right\} \]A plot of the above 4 expressions is attached. They are in red, blue, yellow and green in that order.

Answer 6

yes y = x – 3x2 + 10 is correct.