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Simplify (7b2 – 3b + 2) + (5b2 – 8b – 4) 12b2 + 5b – 2 12b2 + 5b + 6 12b2 – 11b – 2 12b2 – 11b + 6
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just combine like term by getting rid of the parenthesis... \[\huge (7b^2 – 3b + 2) + (5b^2 – 8b – 4) \]
so 12b2 + 5b + 6?
how did you get 5b ?
because 3-8=-5? and i kept the b term
\[\huge (7b^2\color {red}{-3b}+2) +(5b^2\color {red}{-8b}-4) \]
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\[\huge \color {red}{-3b} + \color {red}{-8b}=-11b \]
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