Question

Find

Answer 1

\[\int\limits_{?}^{?} \sin 2x/\sin x dx\]

Answer 2

u=sinx

Answer 3

\[\int \frac{\sin 2x}{\sin x} dx \implies \int \frac{2\sin x \cos x}{\sin x} dx \implies 2 \int \cos x dx\]
does that help?

Answer 4

ya

Answer 5

but how did u get 2 sinx cosx?

Answer 6

\[\sin (2x) = 2\sin x \cos x\]

Answer 7

i know that last part is 2 sinx +c

Answer 8

trig theorem thingy...doubla angle formula was it?

Answer 9

k i see

Answer 10

\[\sin (x + y) = \sin x \cos y + \sin y \cos x\]

Answer 11

anyway... sin (2x) = 2sinxcosx lol

Answer 12

thank for the help

Answer 13

@lgbasallote

Answer 14

welcome welcome