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find the inverse of the function f(x)=x^3-8 (urgently needed plz)
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y = x^3 - 8 Make x the subject.
i have four options to choose from Not a one-to-one function 2) f^-1(x)= 3sq x+8 3) f^-1(x)=3sq x-8 4) f^-1 (x) = 3 sqx=8
which one would be the right option
take f^-1(y)=x y=x^3-8 \[\sqrt[3]{y+8}=x\] so f^-1(y)=\[\sqrt[3]{y+8}\]
2) f^-1(x)= 3sq x+8 ur answer
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thankyou so much.
medal plz :)
im new to this thing. how do u do that?
i'm new too. You give a medal by clicking on "best response".
yep i got it thankyouuu! :D
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But I don't think I can give myself a medal...
yep i think so too
a medal for you from me then...
awww thankyou
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