Question

find the inverse of the function .
f(x)=6x^3 + 3

Answer 1

\[ y= 6x^3 + 3\]
\[x = 6y^3 +3\]
\[=> 6y^3 = x-3\]
\[ y^3 = \frac{x-3}{6}\]

Answer 2

i think that youre able to do it now..

Answer 3

Let f(x) = y

So:

\[y = 6x^3 + 3\]

\[6x^3 = y - 3\]

Divide by 6 both the sides..

\[x^3 = \frac{y}{6} - \frac{1}{2} \implies x = \sqrt[3]{\frac{y}{6} - \frac{1}{2}} \]

Answer 4

Just flip x and y now and that will be your \(f^{-1}(x) ..\)

Answer 5

so the final answer is

Answer 6

f^-1 (x) =3 sq x-3/6

Answer 7

? is that right?

Answer 8

Don't you think that will be x/6 ??

Answer 9

abbey is right

Answer 10

Rest is fine...

Answer 11

Yes you are right if you put that in brackets..

Answer 12

\[\large f^{-1}x=\sqrt[3]{\frac{x-3}{6}} \]

Answer 13

If you mean to say this :

\[f^{-1}(x) = \sqrt[3]{\frac{x - 3}{6}}\]

Answer 14

Well Done...

Answer 15

thank you so much guys!!!!!! i owe u BIG time

Answer 16

Welcome dear...