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OpenStudy (anonymous):
i got 3x√x over x. is that correct?
OpenStudy (anonymous):
no...its not. show me what u did.
OpenStudy (anonymous):
first i simplified the √x^3 and got x^2√x
OpenStudy (anonymous):
then multiplied the top and bottom by √x to get rid of the radical in the denominator. so i have 3x√x over x^2. but my options don't even have that so i went with 3x√x over x
OpenStudy (anonymous):
that's where u went wrong...look here:
\[\sqrt{x ^{3}} = \sqrt{x ^{2}x} = x \sqrt{x}\]
this is what u should get after simplification.
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OpenStudy (anonymous):
yep. forgot you had to split them first. thank you
OpenStudy (anonymous):
sure, no prob!
OpenStudy (anonymous):
still can't find the answer
OpenStudy (anonymous):
-_-
OpenStudy (anonymous):
why not? multiply what i got earlier with 3x.
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OpenStudy (anonymous):
well I'm dividing 3x by x√3 so its not multiplying
OpenStudy (anonymous):
wait...ur question is \[3x / x \sqrt{3} ?\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
oh! i got it wrong! my bad!
well...then first of all, cancel out the x's. then rationalize the denominator.
OpenStudy (anonymous):
so 3/x?
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