Question

set up the partial fraction: integral of [dx/x(x^2-1)]

Answer 1

\[\LARGE \frac{1}{x(x^2 - 1)} \implies \frac{1}{x(x+1)(x-1)}\]
does that help?

Answer 2

ok so a/x..+..b/(x+1)..+..c/(x-1)?

Answer 3

you got it

Answer 4

thanks

Answer 5

\[\frac{A}{x} + \frac{B}{x+1} + \frac{C}{x-1}\]
welcome ^_^