Question

(y^2-16)/(y^2-25)*(y^2+2y-15)/(y^2-7y+12) i have to multiply help ASAP thanks

Answer 1

\[\frac{\left(y^2-16\right) \left(y^2+2
y-15\right)}{\left(y^2-25\right)
\left(y^2-7 y+12\right)}=\frac{(y-4) (y+4)
(y+5) (y-3)}{(y-5) (y+5) (y-4)
(y-3)}=\frac{y+4}{y-5}
\]

Answer 2

gracias

Answer 3

@thania1 did you get it?

Answer 4

yw

Answer 5

yups merci

Answer 6

pas de quoi