Question

(x^2-9)/(x^3+3x^2) divide by (x^2+x-12)/(x^3+9x^2+20x) help ASAP!

Answer 1

when?

Answer 2

\[
\frac{\left(x^2-9\right) \left(x^3+9 x^2+20
x\right)}{\left(x^2+x-12\right)
\left(x^3+3 x^2\right)}=\frac{(x-3) (x+3)
x (x+4) (x+5)}{(x-3) (x+4) x^2
(x+3)}=\frac{x+5}{x}
\]

Answer 3

merci

Answer 4

Avec plaisir