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(7/6t^2)- (1/3t) how do I subtract this?
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\[ \frac{7 t^2}{6}-\frac{t}{3}=\frac{1}{6} \left(7 t^2-2 t\right) \]
gracias
and then?
That is it
gracias
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Is this (1/3t) (1/3) t or 1/(3 t)?
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