Question

(9/x^2-6x+9)+(2/x^2-9) how do I add this?

Answer 1

\[
\frac{9}{x^2-6
x+9}+\frac{2}{x^2-9}=\frac{2}{(x-3)
(x+3)}+\frac{9}{(x-3)^2}=\frac{11
x+21}{(x-3)^2 (x+3)}

\]

Answer 2

gracias

Answer 3

w