how do i determine the largest interval (a,b) for which Theorum I guarantees the existence of a unique solution on (a.b) to the given initial value problem: xy''' - 3y' + e^(x)y = X^(2) - 1 ; y(-2)=1, y'(-2)=0, and y''(-2)=2

Question

how do i determine the largest interval (a,b) for which Theorum I guarantees the existence of a unique solution on (a.b) to the given initial value problem: xy''' - 3y' + e^(x)y = X^(2) - 1   ; y(-2)=1, y'(-2)=0, and y''(-2)=2

anonymous · Answer

i have the answer, just need to know how

anonymous · Answer

Why does everyone hate differential equations?... I don't understand..........

anonymous · Answer

Even i don't understand it! thats y i hate it! :)