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5x²+5x-12 / (x-1) = 0
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solve for x?
yup do you do LCD ?
no..you just cross multiply
\[5x^2+5x - 12 = 0(x-1)\] \[5x^2 + 5x - 12 = 0\] now factor out and solve for x
oops typo 2x^2+5x-12=0
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then it's \[2x^2 + 5x - 12\] factor out and solve for x
(2x-x) (x-4)
(2x-3)*
\[(2x-3)(x-4) = 2x^2 -11x + 12\]
you made a wrong sign somewehre
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yeah (2x+3) (x-4)
thankss !
welcome :D
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