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Mathematics 19 Online
OpenStudy (anonymous):

Three letters are taken from the word YAHOO to form 3 letter words. How many words can be made?

OpenStudy (experimentx):

\[ \binom{4}{3} 3!\]

OpenStudy (experimentx):

if unique!!

OpenStudy (anonymous):

is this combinations or binomial probability?

OpenStudy (experimentx):

just combination and then permutation

OpenStudy (anonymous):

i think that will help u

OpenStudy (anonymous):

ok thanks. but how would you know that its 4C3? since there 5 letters in YAHOO

OpenStudy (rsadhvika):

@experimentX you missed words with teo O's

OpenStudy (rsadhvika):

im not sure...

OpenStudy (rsadhvika):

its two O's

OpenStudy (experimentx):

two O's is counted as one ... if only one O is allowed.

OpenStudy (anonymous):

oh i get it. thanks!

OpenStudy (experimentx):

if both O's are allowed, then we have 5 choices out of 3

OpenStudy (rsadhvika):

5 choices are there. but two O's cant permute, so it should be 5c3/2! ?

OpenStudy (rsadhvika):

5P3/2!

OpenStudy (rsadhvika):

never mind pls i get confused easily...

OpenStudy (experimentx):

not really ... we should have different cases under different constrains as @yahoo posted the link case 1: only one O's is allowed case 2: both O's are allowed <--- here it's divided by 2! case 3: no O's is allowed

OpenStudy (anonymous):

how would to tell the difference if its permutations or combinations?

OpenStudy (experimentx):

combination is just choosing permutation is arranging

OpenStudy (anonymous):

ok thank you!

OpenStudy (experimentx):

eg. choose 3 people out of 5 <--- combinations choose 3 people out of 5 and arrange them in a line <--- permutation

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