If f(x) = 7x-4, find f(3)-2f(-2)
where do you need help for this? what is confusing?
\(f(x)=7x-4\), find \(f(3)-2f(-2)\).
\(f(x)=7x-4\), when you are asked to find the solution of \(f(c)\) of any function, where c is a number/constant or whatever, simply plug in what you have in these parentheses in \(x\) and solve.
Now can you apply what I just told you to your problem?
@qasaali Let her try :)
ok zepp
i try wait
E.g.: Given \(\large f(x)=7x-4, \text{find f(c)}; f(c) = 7c-4\).
let me help her
You can do it >:D
i need a help guys
First can you find f(3)?
\(\large \text{Given }f(x) =7x-4, \text{Find f(c);} \\\large f(c)=7c-4\) \(\large \text{Given }f(x) =7x-4, \text{Find f(3);} \\\large \text{?}\)
wait i almost get it
f(3)=7(3)-4 f(3)=21-4 f(3)=17
yeah i got 17 also
Great! but your actual problem is to find \(f(3)-2f(-2)\), now you've understood the concept, this should be easy! :D
\(f(3)-2f(-2)\) Value of f(x) when x = 3 minus Twice the value of f(x) when x = -2
is the answer 73 ?
it looks like 17-2(-56) = 73
u c we have 21 for f(3) the second step would be finding 2f(-2)
\[\text{Given}~f(x) = 7x-4, \text{Find}~f(3)-2f(-2);\\\]\[\large \begin{align} &=(7(3)-4))-2(7(-2)-4))\\ &=17-2(-14-4)\\ &=17-2(-18)\\ &=17+36\\ &=53 \end{align}\]
Umm
f(-2)=7(-2)-4 f(-2)=-14-4 f(-2)=-18*2 f(-2)=-36
therefore=21-36= -15
i got 53
@qasaali It's 17, not 21, and it's -(-36)
17-(-36)=17+36=53
17-2(-18) = 53
@glares25 Correct! Good job! :)
ok sorry for the silly mistake (-)*(-)=+ so the last answer will be 36+17=53
THANKS A LOT GUYS :D i probably dont figured it out if u didn't help me :)
You are welcome :)
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