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simplyfy
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|dw:1343406525491:dw|
\[\huge \frac{x^a}{x^b} = x^{a-b}\]
a^m/a^n = a^(m-n)
\[x^7=x^2\times x^5\]
a = 2 here and b = 7 here..
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so -4
x^2/x^7 = x^(2-7) = x^-5 = 1/x^5
2 - 7 = ??
a=-4
2 - 7 = ???
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but it cant be -4
2 - 7 = 2 - 2 -5
-5
but thats not a choice
dont forget x
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x=-5 isnt a choice thoguh but there is x=5
and 1/x^5
\[a^{-1}=\frac1a\]
\[a^{-n}=\frac1{a^n}\]
sio the answer is |dw:1343406961587:dw|
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