can anyone check this answer?
7x^2+7y^2+56x+28y-35=0

x=(-4+sqrt21,0), (-4-sqrt21,0)
y=(0,5),(0,1)

Question

can anyone check this answer?
7x^2+7y^2+56x+28y-35=0

x=(-4+sqrt21,0), (-4-sqrt21,0)
y=(0,5),(0,1)

anonymous · Answer

can u explain a little more...tnx b4...

anonymous · Answer

This is the equation of a conic section.  It will be a curve, it doesn't have a unique solution.  What is your answer supposed to represent?

anonymous · Answer

Circle equation.. I just want to see if I got the intercepts correct

anonymous · Answer

It's not a circle.

anonymous · Answer

You can factor out the 7, multiply by 1/7
x^2 + y^2 + 8x + 4y - 35 = 0
the extra x and y terms make it not a circle.

anonymous · Answer

my problems says: A circle has and equation of: 7x^2+7y^2+56x+28y-35=0
find intercepts

anonymous · Answer

Yeah, sorry.

anonymous · Answer

@telliott99 
no problem with ur work
u just forgot to divide 35 by 7...:)

anonymous · Answer

and complete the squares.  That's the key idea.

anonymous · Answer

equation of circle

$ (x+4)^2+(y+2)^2=25 $