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A grocer bought a box of soap containing 72 bars for $49. Some bars he sold at 3 bars for $2.50 and the rest were sold at 70 cents a bar. This gave a profit of $7.80. How many bars did he sell at each price?
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he has 72 bars so a+b=72 also the 3 for 2.5 would make it aprox. .83 a bar so it would also be .83a+.70b=56.80 solve for a or b and substitute .83(72-b)+.70b=56.80 59.76-.83b+.70b=56.80 59.76-.13b=56.80 -.13b=-2.96 b=22.76 23 bars at .70 and 49 bars 3 for 2.50
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