The length of a rectangular table is given by 3x+5 cm and width is given by 2x-7 cm. Express the area of the rectangle in terms of x.
(a+b)*(c+d)= a*c+b*c+a*d+b*d where a=3x b=5 c=2x d= -7
area = length x width therefore \[A = (3x+5)(2x-7)\] expand this and you'll get your answer do you need more help?
ahmmm.. thank you.. really help it a lot..
welcome :D
The base of a triangle measures 3y+7 inches. Express the area of the triangle in terms of y..
area of a triangle is usually 1/2 base*height could you draw a picture
not enough info
The base of a triangle measures 3y+7 inches. Express the area of the triangle in terms of y..
is it an equilateral triangle?
The length and width of a rectangle are given by 2 consecutive odd integers. Write the expression of the area of the rectangle.
area of a rectangle is length*width let x be an odd number and the length then the next consecutive odd integer would be x+2 and this would be the width so just multiply the length and width
i cant understand..
lets say x = 3 the next consecutive odd number would be 5 so what must we do to x in order to get 5?
what is the first number?
x=3 x+b=5 what is b
2?
or 3 because its odd?
so instead of x=3 we have x= an odd number right?
the next consecutive odd number would be the original odd number +2 so (x+2)= next consecutive odd number if x is an odd number
so what number should i apply in the problem?
you shouldnt apply a number for the problem if it is not given, instead you use a variable like x, or y, or m, etc
so x= length (x+2)= width Area of a rectangle= length*width Area= x*(x+2) distribute x state that x must be an odd number
but in my problem the length and width in unknown?
you're told that the length and width are 2 consecutive odd integers
how can i get that?
please give me an illustration..
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