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Mathematics 8 Online
OpenStudy (anonymous):

factors of 2x²+2x-12

OpenStudy (lgbasallote):

break down the middle term \[2x^2 - 6x + 4x - 12\] factor out common factors \[2x(x - 3) + 3(x-3)\] does that help?

OpenStudy (lgbasallote):

the last step would be to factor it out further

OpenStudy (anonymous):

easier if you factor 2 out first

OpenStudy (lgbasallote):

uhmmm i made a typo...should be \[2x(x-3) +4(x-3)\]

OpenStudy (anonymous):

\[(2x+4)(x-3)\]

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