Question

What is the remainder of (9^6 +1)
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2^3

Answer 1

in order to find remainder,reach to the final answer and then multiply the decimal part from the divisor.so in practice,
\[(9^{6}+1)/ 2^{3}\]=66430.25
so take the decimal part(0.25) and multiply it by divisor(8),
hence,the remainder is 2.