Question

Solve the following quadratic equation.
x^2-9x=0

Answer 1

okay so now factor the x^2-9x :)

Answer 2

what would the answer be?

Answer 3

you have to factor x^2-9x ....you should get (x+3)(x-3) and then you set those two equal to zero like this: x+3=0 and x-3=0 and then you solve them for x and get x=-3 and x=3

Answer 4

careful...

Answer 5

so your final answer is\[x=\pm3\]

Answer 6

but 3 times 3 isn't 9x?

Answer 7

\[x^2 - 9x = 0\]
factor out
\[x(x-9) = 0\]
set each factor to 0
\[x = 0; \; x = 9\]

Answer 8

oh i forgot there was an x :O

Answer 9

happens to the best of us

Answer 10

lol..sorry about that...thanks lgbasallote :)

Answer 11

it was my duty as the avatar

Answer 12

thanks avatar! :D