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OpenStudy (anonymous):
Solve the following quadratic equation, expressed in factorized form. (x-6)(x+2)=0
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OpenStudy (anonymous):
set both of those equal to zero \[x-6=0\]and\[x+2=0\]then solve for x
OpenStudy (anonymous):
x=6 or x=-2?
OpenStudy (anonymous):
yup :)
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