Question

algorithm for sum of digits?

Answer 1

There is already a question about that, and some guys answered it, so just search for it.
I think the title is sum of two numbers or something like that.
Its solved using C/C++.

Answer 2

u mean 1234
its sum as 10 like this??

Answer 3

@ Zaid123
try yourself thinking that a number is made of digits, each one of them representing a particular power of 10 ...

Answer 4

@zaid123 its nothing simple in c++,just u have to use divide and remainder function.

Answer 5

Are there no limits like the input must be at most 9,999?
Try thinking.

headers
main()
{
int input,thousands,hundreds,tens,ones,sum;

printf("Input a number at most 9999");
scanf("%d",&a);
thousands = input / 1000;
hundreds = input / 100 % 10;
tens = input / 10 % 10;
ones = input % 10;
sum = thousands + hundreds + tens + ones;
printf("%d",sum);
}

Answer 6

If someone enter a digit than it will print the some of all the digits.For ex. if number is 6789 than answer will be 30.
Solution:-
I am using c.
void main()
{
int num,sum=0; //for storing the number.
while(num>=1)
{
int a; // for storing a digit of the number.
a=num%10; //we will get a single digit.
sum=sum+a;
num=num/10;
}
Ex.
if input will be 123.
than first time
while(123>=1) will be true and
a=3,sum=3,num=12.
second time while(12>=1) will be satisfied and
a=2,sum=5,num=1.
third time while(1>=1) will be true.
a=1,sum=6,num=0;
fourth time while(0>=1) will be false and loop will be terminated.