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What is the sum of the arithmetic sequence 4, 11, 18 …, if there are 26 terms?
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Tn=a+(n-1)d d= common difference a= first term n = no. of term Sn=0.5(a+l) l= last term
d = 7 .thats all i got :(
d = 7, a = 4, n = 26...
a=4 d=7 there fore T26=4+(25)7 = 179
A) 1,482 B) 1,534 C) 2,379 D) 2,470
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those are my choices
well i did a slight mistake in formula Sn=0.5n(a+l) so Sn=0.5*26*(4+179)
its 2379
i got 2327 but thats not a choice
u r doing wrong its Sn=0.5*26*(4+179)
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u got it now???
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