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Evaluate the expression. 10 P 4 A. 5040 B. 720 C. 1 D. 10
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= 10*9*8*7
=90 * 56
use the formula \[^{n}P _{k} = \frac{n!}{(n - k)!}\] n = 10 and k = 4
so 5040
right
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i use a 'short cut' to do these but you should know formula
10 P 3 for example = 10*9*8
i understand thank you so a 11 p 5 is 11*10*9*8*7
yea and also 11 P 8 is same as 11 P 3 (11-8 = 3) - makes that easier to work out
for combinations where the order doesn't matter you proceed like this 10 C 4 = 10*9*8*7 ------- 4*3*2*1 - number of digits on bottom = number on top
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