Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − ___

Numerical Answers Expected!

#INeedAnAnswer

Answer 1

since x=-8 and x=2 then
x+8=0 and x-2=0
ok?

Answer 2

is that the anwser ?

Answer 3

sorry
\[ \large (x+8)(x-2)=x^2+6x-16 \]

Answer 4

sorry wht ?

Answer 5

now u have
\[ \large y=x^2+6x-16 \]
then
\[ \large y+16+9=x^2+6x+9 \]
\[ \large y+25=(x+3)^2 \]
and this has vertex (-3,-25) as required

Answer 6

sooo its -3,-25 ?

Answer 7

16