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this problem is under linear equations, 2 square root of x+3 = 7. Need help?
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Try squaring both sides.
\( \color{Black}{\Rightarrow \sqrt{x + 3}^2 = 7^2}\)
You will get \(x + 3 = 49\), now subtract 3 from both sides.
\[2\sqrt{x+3} = 7\] square both sides \[(2\sqrt{x+3})^2 = 7^2\] \[4(x+3) = 49\] can you do it now? or do you need more help?
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I missed the 2.
Crappy explanation, but you get the point.
I get it now, thank u.
welcome welcome :D
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