Question

sqrt{b2-4ac};b=3,a=-1,c=-2

Answer 1

You just plug in values, so if you are given a question like
73x^2;x=2
then you will plug the 2 inside x.
73(2)^2

Answer 2

substitute
\[\sqrt{(3)^2 - 4(-1)(-2)} \implies \sqrt{9 - 8}\]

Answer 3

So, you plug in and get \( \sqrt{3^2 - 4(-1)(-2)}\)

Answer 4

@rannsan Why did you close that question?