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Find the rule of the inverse function of...
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\[f(x)=1-\frac{1}{\sqrt{4-x}}\]
equalise f(x)=y bring the RHs part in terms of y
I tried but it all got confusing and I think I got the wrong answer :S
y=1-1/root(4-x) 1-y=1/root(4-x) net u try bring interms of y
Thanks I'll try again
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\[y=1-\frac{1}{\sqrt{4-x}} \implies \frac{1}{\sqrt{4-x}} = 1-y \implies \frac{1}{4-x} = (1-y)^2\implies 4 - x = \frac{1}{(1 - y)^2}\] \[x = 4 - \frac{1}{(1-y)^2}\]
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