Question

The distance travelled in 2 nd second is 12m , and 20 m in 4 th second what will the distance covered in 4 seconds after the 5 th second?

Answer 1

v=d2-d1/t2-t1=20-12/4-2=4ms^-1
so now 4 seconds after 5th second wil be
4*4 seconds=16m
this distance is travelled after 5th second then distance travelled at 5th second is
20+4m=24m
so answer wil be distance at 5th second +distance after 4 seconds
24+!6=40

Answer 2

@Yahoo!

Answer 3

Dn = U + a/2 (2n-1)

Answer 4

@theyatin

Answer 5

well @yahoo you were teaching or asking??
sorry i f i am wrong this is all i have. . .

Answer 6

U r correct lol

Answer 7

40m is the answer

Answer 8

@Yahoo!
well i dont always follow topology ;)

Answer 9

thats ok.............thxxxx a lot