Question

If x cannot equal 3 or -4, and 7x-21/x-3 = x^2-x-20/x+4, what is the value of x?
Choices are:
-12
4
7
10
12

Answer 1

\[\large \frac{7(x-3)}{(x-3)} = \frac{(x-5)(x+4)}{(x+4)}\]

Cancel what you can cancel here..

Answer 2

(x-3)(X^2-x-20) = (7x-21)(x+4)

(x-3)(x-5)(x+4) = 7(x-3)(x+4) Cancel(x+4) and (x-3) from both sides

you will get: x-5 = 7

So x = 12

Answer 3

Thank you!!

Answer 4

Welcome dear...

Answer 5

i looked at my answer key but it says it should be -12..