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PLEASE HELP!!!! If sin = -3/5 , find sin 2theta given that θ is in the 3rd quadrant.
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does anyone know how to solve this??
do you know how to use arcsin?
yes
oh wait... so is it that sin(x)=-3/5 or sin(2x)=-3/5 ?
\[\sin 2 \theta \]\ theta=-3/5
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well plug in theta and then look for sin(2x) on the identity sheet.
i did but i didnt get an answer what did u get??
im getting decimals
is it 9/25?
hello??
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sin2T=sinTcosT, since, sinT=3/5, cosT=4/5 so, sin2T= 2 sinTcosT = 2.(3/5.4/5) = 24/25, since the Theta in quadrant III, theta will be = negative...so = -24/25
soory, sin2T = 2. sinT.cosT
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