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Simplify: x^2-16/x^2-8x+16
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:/ Maybe this can help? http://www.wolframalpha.com/input/?i=%28x%5E2-16%29%2F%28x%5E2-8x%2B16%29
alright, i checked my answer with it & i got it right
ok let me do this since \[\Large (a^2-b^2)=(a+b)(a-b)\] then \[\Large (x^2-16)=(x^2-(4)^2)=(x+4)(x-4)\] now factoring the denominator
\[\large \frac{x^2 - 16}{x^2 -8x + 16} \implies \frac{(x+4)(x-4)}{(x-4)(x-4)} \implies \frac{x+4}{x-4}\]
yes, thats what i got
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\[\Large (x^2-8x-16)=(x^2-4x-4x+16)\] \[\Large (x^2-4x-4x+16)=(x(x-4)-4(x-4))=(x-4)(x-4)\]
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