Question

find the inverse laplace transform of F(s)= (s+5)/((s^2+9)^2)

Answer 1

first I would do partial fractions to expand

Answer 2

so (s+5)/(s^2+3^2)^2 = s/(s^2 + 3^2)^2 + 5/(s^2+3^2)^2

Answer 3

on tthe left you want it to be the form os t*sin(wt)

Answer 4

so s/(s^2+3^2)^2 = ((2s(3))/6(s^2+3^2)^2

Answer 5

= t*sin(3t)

Answer 6

err = (1/6)(t*sin(w*t))

Answer 7

you with me so far?

Answer 8

sure ..continue please

Answer 9

Hellooooo ??