Question

Howdy ho everyone, I am trying to get an HTML page source content from this site: "http://207.200.96.231:8008" using java. However the default libraries of java did not help me in this one. I also tried using this tutorial: http://blog.codehangover.com/read-html-with-java-then-7-fun-things-to-do-to-it/ but it did not work either. I think the problem occurs because of a security protection of the site. Any ideas of how to implement the code? Or are there any libraries that can serve my need?

Answer 1

I also tried this code but it doesn't work with your website, it refuses the connection and it's as you said, security reasons:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
public class Acess {
public static void main(String[] args) {
String urltext = " http://207.200.96.231:8080 ";
BufferedReader in = null;
try {
URL url = new URL(urltext);
in = new BufferedReader(new InputStreamReader(url.openStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
System.out.println(inputLine);
}
} catch (Exception e) {
e.printStackTrace();
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
}

Answer 2

try {
URL url = new URL(" http://207.200.96.231:8008/7.html ");
HttpURLConnection urlConnection = (HttpURLConnection)url.openConnection();
urlConnection.setRequestProperty("User-Agent", "Mozilla/5.0");

InputStream is = urlConnection.getInputStream();
BufferedInputStream in = new BufferedInputStream(is);
int c;
while ((c = in.read()) != -1) {
System.out.write(c);
}
urlConnection.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

This code got it working. Shoutcast station wants a user-agent to access its contents and adding the:

urlConnection.setRequestProperty("User-Agent", "Mozilla/5.0");

solved my issue. Thanks anyways :)

Answer 3

Ah good then and you're welcome.