Question

(2x)/(2x+1)=(2x+1-1)/(2x+1)

How?

Answer 1

because 1-1=0

Answer 2

I don't understand why it's added to the numerator.

Answer 3

Does it just serve the purpose of being able to break up the equation into (2x+1)/(2x+1)-(1)/(2x+1)?

Answer 4

I think this is done to form partial fractions:
\[(2x+1)/(2x+1)-1/(2x+1) \]

Answer 5

yes.

Answer 6

ok, I'll just have to dig deep to remember my algebra rules, thanks