Question

PLEASE HELP! Angle A in Quadrant III and 0degrees
14 years ago

Answer 1

ok
since tangent is positive in third Quad..so

using Pythagorean theorem
\[\Large altitude=\sqrt{5^2-2^2}=\sqrt{16}=4\]
so
\[\Large tangent=\frac{altitude}{base}=\frac{4}{2}\]