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2*n+2*n-1 divided by 2n+1-2*n= 3/2
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is N and n same?
n
ok .. \[\large{\frac{2n+2n-1}{2n-1-2n}=\frac{3}{2}}\]
\[\large{4n-1=\frac{6n-3-6n}{2}}\] \[\large{8n-2=6n-3-6n}\]
yes
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\[\large{8n-2=-3}\] \[\large{8n-2+3=0}\]
can you solve further ? ?
@shivraj .. what r u getting for the value for n ?
no i dont hav any idea
ok .. : -2 + 3 =?
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1
right .. now 8n -1 = 0 : can u do it now?
yes
so what r u getting?
3/2
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8n - 1 = 0 8n - 1 + 1 = 0 +1 8n = 1 n = 1/8 ..
check it again @shivraj
ok
Is 1/8 the answer @mathslover
See, here: \[\large 8n - 2 + 3 = 0 \implies 8n = -1\] \[\large \color{green}{n = \frac{-1}{8}}\]
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@shivraj are you getting??
oh yes it is -1/8 ..
thnks
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