Question

x*3+4x*2-9x-36=0 solve factor by grouping

Answer 1

i suppose * refers to exponents

Answer 2

so group them
\[(x^3 + 4x^2) - (9x + 36)\]
factor:
\[x^2(x+4) - 9(x+4)\]
does that help

Answer 3

please explain

Answer 4

which part?

Answer 5

all sir

Answer 6

first i put a parenthesis

Answer 7

ok

Answer 8

this will help -- http://www.youtube.com/watch?v=-hiGJwMNNsM

Answer 9

so x^3 + 4x^2 - 9x - 36

became

(x^3 + 4x^2) - (9x + 36)
^that became 9x+36 because it's like i factored out -1 form -9x and -36

Answer 10

then i factored out x^2 from x^3 + 4x^2

and 9 from 9x + 36 so it gave me

x^2(x = 4) - 9(x+4)

and that's all that happened`

Answer 11

that's supposed to be x^2(x+4)

Answer 12

you are now up to speed

Answer 13

k

Answer 14

b

Answer 15

thnks

Answer 16

welcome