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find range and domain of (x^2 + 2x + 1)/(x^2-8x+12)?
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Can you factorize denominator ??
\[x^2 - 8x + 12\neq0\]
Yes.. Firstly factorize it..
(x-6) (x-2)
Yes So what x cannot take here?
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so Domain = R-{ 2 ,6}
Yes right..
Then range
For range put f(x) = y firstly factorize the numerator here..
so.......wat to do?
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Call @experimentX here.
I am bad experience when quadratic comes in range..
can you make partial fractions?
wat is partial fractions?
wait ... i'll look for a method.
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y = f(x) y(x^2-8x+12) = x^2 + 2x +1
http://www.wolframalpha.com/input/?i=partial+fractions+%28x^2+%2B+2x+%2B+1%29%2F%28x^2-8x%2B12%29
x^2(y-1) - x(8y + 2) + (12y -1) =0
i got such quad eq
i got 4y^2 + 21 >= 0
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