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Mathematics 14 Online
OpenStudy (osuxbucks15):

Write the standard equation of the circle in the graph. (x + 3)2 + (y – 2)2 = 9 (x – 3)2 + (y + 2)2 = 9 (x – 3)2 + (y + 2)2 = 18 (x + 3)2 + (y – 2)2 = 18

OpenStudy (osuxbucks15):

Parth (parthkohli):

Hint: Find the radius, and the center coordinates; plug them into the standard equation of a circle.

Parth (parthkohli):

\[(x - h)^2 + (y - k)^2 = r^2 \] Where (h,k) = center coordinates, r = radius.

OpenStudy (osuxbucks15):

is the radius 2.5

Parth (parthkohli):

Nopes. It's 3.

Parth (parthkohli):

Notice how every half unit on the graph represents a unit.

OpenStudy (osuxbucks15):

o ok

Parth (parthkohli):

1.5 units on graph = 3 units.

Parth (parthkohli):

And what about the center coordinates?

OpenStudy (osuxbucks15):

(3,-2)

Parth (parthkohli):

Naw naw.

Parth (parthkohli):

You substitute h and k with 3 and -2.\[(x - 3)^2 + (y - (-2))^2 = 3^2 \]

Parth (parthkohli):

What does that give you?

OpenStudy (osuxbucks15):

y does it say math processing error?

Parth (parthkohli):

Never mind that. Refresh the page.

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