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@across do you know?
[-5,1]
nice, how did you get that?
|x+2| <= 3 -(x+2) <=3 -x-2<=3 -x<=5 x>=-5 and x+2<=3 x<= 1 so -5<=x<=1 thus [-5,1]
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with absolut values you must look at both cases one where you take the negative of the inside and one where you dont.
nice thanks!
np
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