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($359.99+$199.99)+6x ≤ 2000
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($359.99+$199.99)+6x ≤ 2000
do you know how to start this problem
First you want to get all non-x terms on one side. Adding 359.99+199.99 you get 559.98. subtract this from both sides to end up with \[6x \le 1440.02 \] Then you just solve for x as you normally would. \[x \le 240.0033\] This gives you a range of x values that will solve the equation. It's pretty much saying that any value you put in for x that is equal to, or less than 240.0033 repeating, will make the equation true.
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