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For each of these functions, do the following: (1) Determine if the parabola opens upward or downward; (2) Find the vertex; (3) Find the axis of symettry; (4) Make a table of coordinate pairs; and (5) sketch the graph. y=x^2 -6x +11
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upwards i believe since its a positive in front of the x^2
ok
@Calcmathlete
idk for sure
It is upwards since the x^2 term is positive...
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ok
Formula for the axis of symmetry is \[x = -\frac{b}{2a}\]
oki go on
hello guys!
calc and top
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DOTS DOTS DOTS!, Yo i unfortunately must go to bed. I can study better in the morning
alright nighty night
Alright. You just have to use my formula to get the axis of symmetry. Then plug that in for x and that is your vertex...
cya tomorrow :)
good luck on the final exam
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thx calcmath
np :)
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