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Mathematics 16 Online
OpenStudy (anikate):

For each of these functions, do the following: (1) Determine if the parabola opens upward or downward; (2) Find the vertex; (3) Find the axis of symettry; (4) Make a table of coordinate pairs; and (5) sketch the graph. y=x^2 -6x +11

OpenStudy (anonymous):

upwards i believe since its a positive in front of the x^2

OpenStudy (anikate):

ok

OpenStudy (anikate):

@Calcmathlete

OpenStudy (anonymous):

idk for sure

OpenStudy (anonymous):

It is upwards since the x^2 term is positive...

OpenStudy (anikate):

ok

OpenStudy (anonymous):

Formula for the axis of symmetry is \[x = -\frac{b}{2a}\]

OpenStudy (anikate):

oki go on

OpenStudy (anikate):

hello guys!

OpenStudy (anikate):

calc and top

OpenStudy (anonymous):

DOTS DOTS DOTS!, Yo i unfortunately must go to bed. I can study better in the morning

OpenStudy (anikate):

alright nighty night

OpenStudy (anonymous):

Alright. You just have to use my formula to get the axis of symmetry. Then plug that in for x and that is your vertex...

OpenStudy (anikate):

cya tomorrow :)

OpenStudy (anikate):

good luck on the final exam

OpenStudy (anikate):

thx calcmath

OpenStudy (anonymous):

np :)

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