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x^2-2x-35=0 use the quadratic formula to solve the equation
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...so use the quadratic formula...what's the problem?
This is in the form \(y = ax^2 + bx + c\). THis is the quadratic formula: \[x = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}\]Plug in a, b, and c based on the first thing I said.
i dont know how to solve
Literally, just plug in numbers and simplify... \[x = \frac{2 ± \sqrt{(-2)^2 - 4(1)(-35)}}{2(1)} \implies?\]
ok
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What do you get?
10/2
THat's one. What about the other? \[x = \frac{2 ± 12}{2} \implies x = 1 ± 6\]
So what are your two answers now?
sorry
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