Question

Please help! tan15degrees (using 45degrees and 30degrees)
tan15degrees=

Answer 1

use
\[\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}\] with
\[a=45,b=30\]

Answer 2

\[\tan(45)=1, \tan(30)=\frac{\sqrt{3}}{3}\] plug the numbers directly in to the formula to get your answer

Answer 3

Thank you satellite!